Atlanta Braves Codexery

1948 World Series Game 4

Cleveland takes commanding 3–1 series lead behind Gromek's complete game.

Game 4 of the 1948 World Series featured Steve Gromek of the Indians and Johnny Sain of the Braves, each pitching a complete game. The Indians struck first when Dale Mitchell hit a leadoff single in the first and scored on Lou Boudreau's double, then added to their lead on Larry Doby's home run in the third. Marv Rickert's leadoff home run in the seventh cut the Indians' lead to 2–1, but they held on to take a 3–1 series lead.

event
1948 World Series Game 4
teams_involved
Boston Braves vs. Cleveland Indians
venue
Braves Field, Boston
date
October 10, 1948
outcome
Indians victory (Series lead 3-1)
series_status
Cleveland leads series 3-1 after Game 4
key_figure
Lou Boudreau (Opposing Manager)

Lore & Background

This was the first World Series to be televised beyond the previous year's limited network and was announced by Red Barber, Tom Hussey (in Boston) and Van Patrick (in Cleveland). It was the only World Series played between 1947 and 1958 not to feature a New York team, and the last not won by a New York team until the 1957 Series.

In Their Own Story

The air inside the Polo Grounds was thick with autumn chill and the scent of roasted peanuts, but for the Braves dugout, the only thing burning was the need to survive. As Walker Cooper stepped into the batter's box, the roar of twenty thousand New York fans seemed to fade into a distant hum. He waited, watching the pitch come in low and outside, then swung with every ounce of his rookie hope. The crack of the bat echoed like thunder as the ball soared over the left-field fence, silencing the Giants' faithful and sending the Braves bench erupting into a chaotic celebration that promised more was to come.

Reader's Guide

The Indians won Game 4 by a score of 2–1, taking a 3–1 series lead. Steve Gromek earned the complete-game win for Cleveland, while Johnny Sain took the loss for Boston.

Did You Know?

Frequently Asked Questions

Where was 1948 World Series Game 4 played?

The match took place at Braves Field in Boston on October 10, 1948. This venue served as the home stadium before the franchise eventually moved to Milwaukee and later Atlanta.

Who did the Braves play against in this game?

The Boston Braves faced off against the powerhouse Cleveland Indians during this championship contest. It was a matchup between two strong teams vying for control of the World Series title.

What was the result of Game 4 for the Braves?

The Indians won the game, which shifted the series momentum heavily in their favor. Following this loss, Boston trailed Cleveland by a score of three games to one.

Why is this game remembered by Braves fans today?

It represents a defining moment from the franchise's Boston era before its relocation history began. The intense pitching duel and elimination pressure make it a notable historical footnote for historians.

How did this game affect the series standings?

This victory allowed Cleveland to seize control of the best-of-seven matchup with only one loss remaining for Boston. Ultimately, the Indians went on to win the World Series after taking this commanding lead.

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